(b-2)-5=8-2(b-3)

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Solution for (b-2)-5=8-2(b-3) equation: 



(b-2)-5=8-2(b-3)

We move all terms to the left:

(b-2)-5-(8-2(b-3))=0

We get rid of parentheses

b-(8-2(b-3))-2-5=0



We calculate terms in parentheses: -(8-2(b-3)), so:

8-2(b-3)

determiningTheFunctionDomain
-2(b-3)+8

We multiply parentheses

-2b+6+8

We add all the numbers together, and all the variables

-2b+14

Back to the equation:

-(-2b+14)



We add all the numbers together, and all the variables

b-(-2b+14)-7=0

We get rid of parentheses

b+2b-14-7=0

We add all the numbers together, and all the variables

3b-21=0

We move all terms containing b to the left, all other terms to the right

3b=21

b=21/3

b=7

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