(b-2)(b-8)=0

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Solution for (b-2)(b-8)=0 equation:


Simplifying
(b + -2)(b + -8) = 0

Reorder the terms:
(-2 + b)(b + -8) = 0

Reorder the terms:
(-2 + b)(-8 + b) = 0

Multiply (-2 + b) * (-8 + b)
(-2(-8 + b) + b(-8 + b)) = 0
((-8 * -2 + b * -2) + b(-8 + b)) = 0
((16 + -2b) + b(-8 + b)) = 0
(16 + -2b + (-8 * b + b * b)) = 0
(16 + -2b + (-8b + b2)) = 0

Combine like terms: -2b + -8b = -10b
(16 + -10b + b2) = 0

Solving
16 + -10b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b)(8 + -1b) = 0

Subproblem 1

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Subproblem 2

Set the factor '(8 + -1b)' equal to zero and attempt to solve: Simplifying 8 + -1b = 0 Solving 8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1b = 0 + -8 -1b = 0 + -8 Combine like terms: 0 + -8 = -8 -1b = -8 Divide each side by '-1'. b = 8 Simplifying b = 8

Solution

b = {2, 8}

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