(b-2)(b-4)=0

Solution for (b-2)(b-4)=0 equation:

Simplifying
(b + -2)(b + -4) = 0

Reorder the terms:
(-2 + b)(b + -4) = 0

Reorder the terms:
(-2 + b)(-4 + b) = 0

Multiply (-2 + b) * (-4 + b)
(-2(-4 + b) + b(-4 + b)) = 0
((-4 * -2 + b * -2) + b(-4 + b)) = 0
((8 + -2b) + b(-4 + b)) = 0
(8 + -2b + (-4 * b + b * b)) = 0
(8 + -2b + (-4b + b2)) = 0

Combine like terms: -2b + -4b = -6b
(8 + -6b + b2) = 0

Solving
8 + -6b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b)(4 + -1b) = 0

Subproblem 1
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Subproblem 2
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Solution
b = {2, 4}