(b-2)(b-12)=

Solution for (b-2)(b-12)= equation:

Simplifying
(b + -2)(b + -12) = 0

Reorder the terms:
(-2 + b)(b + -12) = 0

Reorder the terms:
(-2 + b)(-12 + b) = 0

Multiply (-2 + b) * (-12 + b)
(-2(-12 + b) + b(-12 + b)) = 0
((-12 * -2 + b * -2) + b(-12 + b)) = 0
((24 + -2b) + b(-12 + b)) = 0
(24 + -2b + (-12 * b + b * b)) = 0
(24 + -2b + (-12b + b2)) = 0

Combine like terms: -2b + -12b = -14b
(24 + -14b + b2) = 0

Solving
24 + -14b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + -1b)(12 + -1b) = 0

Subproblem 1
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Subproblem 2
Set the factor '(12 + -1b)' equal to zero and attempt to solve:

Simplifying
12 + -1b = 0

Solving
12 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1b = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1b = 0 + -12
-1b = 0 + -12

Combine like terms: 0 + -12 = -12
-1b = -12

Divide each side by '-1'.
b = 12

Simplifying
b = 12
Solution
b = {2, 12}