(b+c)+d=b+(c+d)

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Solution for (b+c)+d=b+(c+d) equation:


Simplifying
(b + c) + d = b + (c + d)

Remove parenthesis around (b + c)
b + c + d = b + (c + d)

Remove parenthesis around (c + d)
b + c + d = b + c + d

Add '-1b' to each side of the equation.
b + c + -1b + d = b + c + -1b + d

Reorder the terms:
b + -1b + c + d = b + c + -1b + d

Combine like terms: b + -1b = 0
0 + c + d = b + c + -1b + d
c + d = b + c + -1b + d

Reorder the terms:
c + d = b + -1b + c + d

Combine like terms: b + -1b = 0
c + d = 0 + c + d
c + d = c + d

Add '-1c' to each side of the equation.
c + -1c + d = c + -1c + d

Combine like terms: c + -1c = 0
0 + d = c + -1c + d
d = c + -1c + d

Combine like terms: c + -1c = 0
d = 0 + d
d = d

Add '-1d' to each side of the equation.
d + -1d = d + -1d

Combine like terms: d + -1d = 0
0 = d + -1d

Combine like terms: d + -1d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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