(b+9)(b+3)=

Solution for (b+9)(b+3)= equation:

Simplifying
(b + 9)(b + 3) = 0

Reorder the terms:
(9 + b)(b + 3) = 0

Reorder the terms:
(9 + b)(3 + b) = 0

Multiply (9 + b) * (3 + b)
(9(3 + b) + b(3 + b)) = 0
((3 * 9 + b * 9) + b(3 + b)) = 0
((27 + 9b) + b(3 + b)) = 0
(27 + 9b + (3 * b + b * b)) = 0
(27 + 9b + (3b + b2)) = 0

Combine like terms: 9b + 3b = 12b
(27 + 12b + b2) = 0

Solving
27 + 12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(9 + b)(3 + b) = 0

Subproblem 1
Set the factor '(9 + b)' equal to zero and attempt to solve:

Simplifying
9 + b = 0

Solving
9 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + b = 0 + -9

Combine like terms: 9 + -9 = 0
0 + b = 0 + -9
b = 0 + -9

Combine like terms: 0 + -9 = -9
b = -9

Simplifying
b = -9
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-9, -3}