(b+6)(b-4)=2b+12

Solution for (b+6)(b-4)=2b+12 equation:

Simplifying
(b + 6)(b + -4) = 2b + 12

Reorder the terms:
(6 + b)(b + -4) = 2b + 12

Reorder the terms:
(6 + b)(-4 + b) = 2b + 12

Multiply (6 + b) * (-4 + b)
(6(-4 + b) + b(-4 + b)) = 2b + 12
((-4 * 6 + b * 6) + b(-4 + b)) = 2b + 12
((-24 + 6b) + b(-4 + b)) = 2b + 12
(-24 + 6b + (-4 * b + b * b)) = 2b + 12
(-24 + 6b + (-4b + b2)) = 2b + 12

Combine like terms: 6b + -4b = 2b
(-24 + 2b + b2) = 2b + 12

Reorder the terms:
-24 + 2b + b2 = 12 + 2b

Add '-2b' to each side of the equation.
-24 + 2b + -2b + b2 = 12 + 2b + -2b

Combine like terms: 2b + -2b = 0
-24 + 0 + b2 = 12 + 2b + -2b
-24 + b2 = 12 + 2b + -2b

Combine like terms: 2b + -2b = 0
-24 + b2 = 12 + 0
-24 + b2 = 12

Solving
-24 + b2 = 12

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '24' to each side of the equation.
-24 + 24 + b2 = 12 + 24

Combine like terms: -24 + 24 = 0
0 + b2 = 12 + 24
b2 = 12 + 24

Combine like terms: 12 + 24 = 36
b2 = 36

Simplifying
b2 = 36

Take the square root of each side:
b = {-6, 6}