(b+4)(b-3)(2b-1)=0

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Solution for (b+4)(b-3)(2b-1)=0 equation:


Simplifying
(b + 4)(b + -3)(2b + -1) = 0

Reorder the terms:
(4 + b)(b + -3)(2b + -1) = 0

Reorder the terms:
(4 + b)(-3 + b)(2b + -1) = 0

Reorder the terms:
(4 + b)(-3 + b)(-1 + 2b) = 0

Multiply (4 + b) * (-3 + b)
(4(-3 + b) + b(-3 + b))(-1 + 2b) = 0
((-3 * 4 + b * 4) + b(-3 + b))(-1 + 2b) = 0
((-12 + 4b) + b(-3 + b))(-1 + 2b) = 0
(-12 + 4b + (-3 * b + b * b))(-1 + 2b) = 0
(-12 + 4b + (-3b + b2))(-1 + 2b) = 0

Combine like terms: 4b + -3b = 1b
(-12 + 1b + b2)(-1 + 2b) = 0

Multiply (-12 + 1b + b2) * (-1 + 2b)
(-12(-1 + 2b) + 1b * (-1 + 2b) + b2(-1 + 2b)) = 0
((-1 * -12 + 2b * -12) + 1b * (-1 + 2b) + b2(-1 + 2b)) = 0
((12 + -24b) + 1b * (-1 + 2b) + b2(-1 + 2b)) = 0
(12 + -24b + (-1 * 1b + 2b * 1b) + b2(-1 + 2b)) = 0
(12 + -24b + (-1b + 2b2) + b2(-1 + 2b)) = 0
(12 + -24b + -1b + 2b2 + (-1 * b2 + 2b * b2)) = 0
(12 + -24b + -1b + 2b2 + (-1b2 + 2b3)) = 0

Combine like terms: -24b + -1b = -25b
(12 + -25b + 2b2 + -1b2 + 2b3) = 0

Combine like terms: 2b2 + -1b2 = 1b2
(12 + -25b + 1b2 + 2b3) = 0

Solving
12 + -25b + 1b2 + 2b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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