(b+4)(b+4)=

Solution for (b+4)(b+4)= equation:

Simplifying
(b + 4)(b + 4) = 0

Reorder the terms:
(4 + b)(b + 4) = 0

Reorder the terms:
(4 + b)(4 + b) = 0

Multiply (4 + b) * (4 + b)
(4(4 + b) + b(4 + b)) = 0
((4 * 4 + b * 4) + b(4 + b)) = 0
((16 + 4b) + b(4 + b)) = 0
(16 + 4b + (4 * b + b * b)) = 0
(16 + 4b + (4b + b2)) = 0

Combine like terms: 4b + 4b = 8b
(16 + 8b + b2) = 0

Solving
16 + 8b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + b)(4 + b) = 0

Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Solution
b = {-4, -4}