(b+3)/5=(3b+3)/3

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Solution for (b+3)/5=(3b+3)/3 equation: 



(b+3)/5=(3b+3)/3

We move all terms to the left:

(b+3)/5-((3b+3)/3)=0

We calculate fractions


b/()+(-((3b+3)*5)/()=0



We calculate terms in parentheses: +(-((3b+3)*5)/(), so:

-((3b+3)*5)/(

We multiply all the terms by the denominator


-((3b+3)*5)



We calculate terms in parentheses: -((3b+3)*5), so:

(3b+3)*5

We multiply parentheses

15b+15

Back to the equation:

-(15b+15)



We get rid of parentheses

-15b-15

Back to the equation:

+(-15b-15)



We get rid of parentheses

b/()-15b-15=0

We multiply all the terms by the denominator


b-15b*()-15*()=0

We add all the numbers together, and all the variables

b-15b*()=0

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