(b+3)(b+4)=

Solution for (b+3)(b+4)= equation:

Simplifying
(b + 3)(b + 4) = 0

Reorder the terms:
(3 + b)(b + 4) = 0

Reorder the terms:
(3 + b)(4 + b) = 0

Multiply (3 + b) * (4 + b)
(3(4 + b) + b(4 + b)) = 0
((4 * 3 + b * 3) + b(4 + b)) = 0
((12 + 3b) + b(4 + b)) = 0
(12 + 3b + (4 * b + b * b)) = 0
(12 + 3b + (4b + b2)) = 0

Combine like terms: 3b + 4b = 7b
(12 + 7b + b2) = 0

Solving
12 + 7b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4 + b)(3 + b) = 0

Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-4, -3}