(b+27+12+3b+8)+2(10+b)=97

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Solution for (b+27+12+3b+8)+2(10+b)=97 equation:


Simplifying
(b + 27 + 12 + 3b + 8) + 2(10 + b) = 97

Reorder the terms:
(27 + 12 + 8 + b + 3b) + 2(10 + b) = 97

Combine like terms: 27 + 12 = 39
(39 + 8 + b + 3b) + 2(10 + b) = 97

Combine like terms: 39 + 8 = 47
(47 + b + 3b) + 2(10 + b) = 97

Combine like terms: b + 3b = 4b
(47 + 4b) + 2(10 + b) = 97

Remove parenthesis around (47 + 4b)
47 + 4b + 2(10 + b) = 97
47 + 4b + (10 * 2 + b * 2) = 97
47 + 4b + (20 + 2b) = 97

Reorder the terms:
47 + 20 + 4b + 2b = 97

Combine like terms: 47 + 20 = 67
67 + 4b + 2b = 97

Combine like terms: 4b + 2b = 6b
67 + 6b = 97

Solving
67 + 6b = 97

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-67' to each side of the equation.
67 + -67 + 6b = 97 + -67

Combine like terms: 67 + -67 = 0
0 + 6b = 97 + -67
6b = 97 + -67

Combine like terms: 97 + -67 = 30
6b = 30

Divide each side by '6'.
b = 5

Simplifying
b = 5

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