(b+2)(2b+3)=

Solution for (b+2)(2b+3)= equation:

Simplifying
(b + 2)(2b + 3) = 0

Reorder the terms:
(2 + b)(2b + 3) = 0

Reorder the terms:
(2 + b)(3 + 2b) = 0

Multiply (2 + b) * (3 + 2b)
(2(3 + 2b) + b(3 + 2b)) = 0
((3 * 2 + 2b * 2) + b(3 + 2b)) = 0
((6 + 4b) + b(3 + 2b)) = 0
(6 + 4b + (3 * b + 2b * b)) = 0
(6 + 4b + (3b + 2b2)) = 0

Combine like terms: 4b + 3b = 7b
(6 + 7b + 2b2) = 0

Solving
6 + 7b + 2b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + b)(3 + 2b) = 0

Subproblem 1
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(3 + 2b)' equal to zero and attempt to solve:

Simplifying
3 + 2b = 0

Solving
3 + 2b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2b = 0 + -3
2b = 0 + -3

Combine like terms: 0 + -3 = -3
2b = -3

Divide each side by '2'.
b = -1.5

Simplifying
b = -1.5
Solution
b = {-2, -1.5}