(b+1)i=5+4i

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Solution for (b+1)i=5+4i equation: 


Simplifying
(b + 1) * i = 5 + 4i

Reorder the terms:
(1 + b) * i = 5 + 4i

Reorder the terms for easier multiplication:
i(1 + b) = 5 + 4i
(1 * i + b * i) = 5 + 4i

Reorder the terms:
(bi + 1i) = 5 + 4i
(bi + 1i) = 5 + 4i

Solving
bi + 1i = 5 + 4i

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1i' to each side of the equation.
bi + 1i + -1i = 5 + 4i + -1i

Combine like terms: 1i + -1i = 0
bi + 0 = 5 + 4i + -1i
bi = 5 + 4i + -1i

Combine like terms: 4i + -1i = 3i
bi = 5 + 3i

Divide each side by 'i'.
b = 5i-1 + 3

Simplifying
b = 5i-1 + 3

Reorder the terms:
b = 3 + 5i-1

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