(b+1)/(b+2)=3

Solution for (b+1)/(b+2)=3 equation:

(b+1)/(b+2)=3

We move all terms to the left:

(b+1)/(b+2)-(3)=0


Domain of the equation: (b+2)!=0

We move all terms containing b to the left, all other terms to the right

b!=-2

b∈R


We multiply all the terms by the denominator


(b+1)-3*(b+2)=0

We multiply parentheses

(b+1)-3b-6=0

We get rid of parentheses

b-3b+1-6=0

We add all the numbers together, and all the variables

-2b-5=0

We move all terms containing b to the left, all other terms to the right

-2b=5

b=5/-2

b=-2+1/2