(b+1)(b-2)(b+3)=

Solution for (b+1)(b-2)(b+3)= equation:

Simplifying
(b + 1)(b + -2)(b + 3) = 0

Reorder the terms:
(1 + b)(b + -2)(b + 3) = 0

Reorder the terms:
(1 + b)(-2 + b)(b + 3) = 0

Reorder the terms:
(1 + b)(-2 + b)(3 + b) = 0

Multiply (1 + b) * (-2 + b)
(1(-2 + b) + b(-2 + b))(3 + b) = 0
((-2 * 1 + b * 1) + b(-2 + b))(3 + b) = 0
((-2 + 1b) + b(-2 + b))(3 + b) = 0
(-2 + 1b + (-2 * b + b * b))(3 + b) = 0
(-2 + 1b + (-2b + b2))(3 + b) = 0

Combine like terms: 1b + -2b = -1b
(-2 + -1b + b2)(3 + b) = 0

Multiply (-2 + -1b + b2) * (3 + b)
(-2(3 + b) + -1b * (3 + b) + b2(3 + b)) = 0
((3 * -2 + b * -2) + -1b * (3 + b) + b2(3 + b)) = 0
((-6 + -2b) + -1b * (3 + b) + b2(3 + b)) = 0
(-6 + -2b + (3 * -1b + b * -1b) + b2(3 + b)) = 0
(-6 + -2b + (-3b + -1b2) + b2(3 + b)) = 0
(-6 + -2b + -3b + -1b2 + (3 * b2 + b * b2)) = 0
(-6 + -2b + -3b + -1b2 + (3b2 + b3)) = 0

Combine like terms: -2b + -3b = -5b
(-6 + -5b + -1b2 + 3b2 + b3) = 0

Combine like terms: -1b2 + 3b2 = 2b2
(-6 + -5b + 2b2 + b3) = 0

Solving
-6 + -5b + 2b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.