(b+1)(b+2)=

Solution for (b+1)(b+2)= equation:

Simplifying
(b + 1)(b + 2) = 0

Reorder the terms:
(1 + b)(b + 2) = 0

Reorder the terms:
(1 + b)(2 + b) = 0

Multiply (1 + b) * (2 + b)
(1(2 + b) + b(2 + b)) = 0
((2 * 1 + b * 1) + b(2 + b)) = 0
((2 + 1b) + b(2 + b)) = 0
(2 + 1b + (2 * b + b * b)) = 0
(2 + 1b + (2b + b2)) = 0

Combine like terms: 1b + 2b = 3b
(2 + 3b + b2) = 0

Solving
2 + 3b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2 + b)(1 + b) = 0

Subproblem 1
Set the factor '(2 + b)' equal to zero and attempt to solve:

Simplifying
2 + b = 0

Solving
2 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + b = 0 + -2
b = 0 + -2

Combine like terms: 0 + -2 = -2
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {-2, -1}