(b(b+12))=189

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Solution for (b(b+12))=189 equation:


Simplifying
(b(b + 12)) = 189

Reorder the terms:
(b(12 + b)) = 189
((12 * b + b * b)) = 189
((12b + b2)) = 189
(12b + b2) = 189

Remove parenthesis around (12b + b2)
12b + b2 = 189

Solving
12b + b2 = 189

Solving for variable 'b'.

Reorder the terms:
-189 + 12b + b2 = 189 + -189

Combine like terms: 189 + -189 = 0
-189 + 12b + b2 = 0

Factor a trinomial.
(-21 + -1b)(9 + -1b) = 0

Subproblem 1

Set the factor '(-21 + -1b)' equal to zero and attempt to solve: Simplifying -21 + -1b = 0 Solving -21 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '21' to each side of the equation. -21 + 21 + -1b = 0 + 21 Combine like terms: -21 + 21 = 0 0 + -1b = 0 + 21 -1b = 0 + 21 Combine like terms: 0 + 21 = 21 -1b = 21 Divide each side by '-1'. b = -21 Simplifying b = -21

Subproblem 2

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {-21, 9}

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