(ab+2)(ab+2)=

Solution for (ab+2)(ab+2)= equation:

Simplifying
(ab + 2)(ab + 2) = 0

Reorder the terms:
(2 + ab)(ab + 2) = 0

Reorder the terms:
(2 + ab)(2 + ab) = 0

Multiply (2 + ab) * (2 + ab)
(2(2 + ab) + ab(2 + ab)) = 0
((2 * 2 + ab * 2) + ab(2 + ab)) = 0
((4 + 2ab) + ab(2 + ab)) = 0
(4 + 2ab + (2 * ab + ab * ab)) = 0
(4 + 2ab + (2ab + a2b2)) = 0

Combine like terms: 2ab + 2ab = 4ab
(4 + 4ab + a2b2) = 0

Solving
4 + 4ab + a2b2 = 0

Solving for variable 'a'.

Factor a trinomial.
(2 + ab)(2 + ab) = 0

Subproblem 1
Set the factor '(2 + ab)' equal to zero and attempt to solve:

Simplifying
2 + ab = 0

Solving
2 + ab = 0

Move all terms containing a to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + ab = 0 + -2

Combine like terms: 2 + -2 = 0
0 + ab = 0 + -2
ab = 0 + -2

Combine like terms: 0 + -2 = -2
ab = -2

Divide each side by 'b'.
a = -2b-1

Simplifying
a = -2b-1
Subproblem 2
Set the factor '(2 + ab)' equal to zero and attempt to solve:

Simplifying
2 + ab = 0

Solving
2 + ab = 0

Move all terms containing a to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + ab = 0 + -2

Combine like terms: 2 + -2 = 0
0 + ab = 0 + -2
ab = 0 + -2

Combine like terms: 0 + -2 = -2
ab = -2

Divide each side by 'b'.
a = -2b-1

Simplifying
a = -2b-1
Solution
a = {-2b-1, -2b-1}