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x in (-oo:+oo)
((((a^1)/3)*b^1)/2)*(((a^2)/3)*b-1) = 0
(((a/3)*b)/2)*(((a^2)/3)*b-1) = 0
1/6*a*b*(1/3*a^2*b-1) = 0
x belongs to the empty set
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