(a/a+5)-2=(3a/a+5)

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Solution for (a/a+5)-2=(3a/a+5) equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

a/a-2+5 = (3*a)/a+5 // - (3*a)/a+5

a/a-((3*a)/a)-5-2+5 = 0

a/a-5-3-2+5 = 0

-4 = 0

a belongs to the empty set

a belongs to the empty set

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