(a/2)+(1/5)=(21/10)

Solution for (a/2)+(1/5)=(21/10) equation:

(a/2)+(1/5)=(21/10)

We move all terms to the left:

(a/2)+(1/5)-((21/10))=0

We add all the numbers together, and all the variables

(+a/2)+(+1/5)-((+21/10))=0

We get rid of parentheses

a/2+1/5-((+21/10))=0

We calculate fractions


50a^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

50a^2/()+2=0

We multiply all the terms by the denominator


50a^2+2*()=0

We add all the numbers together, and all the variables

50a^2=0

a = 50; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·50·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{100}=0$