(a-3)(a-5)=(a-5)(a-3)

Solution for (a-3)(a-5)=(a-5)(a-3) equation:

(a-3)(a-5)=(a-5)(a-3)

We move all terms to the left:

(a-3)(a-5)-((a-5)(a-3))=0

We multiply parentheses ..

(+a^2-5a-3a+15)-((a-5)(a-3))=0


We calculate terms in parentheses: -((a-5)(a-3)), so:

(a-5)(a-3)

We multiply parentheses ..

(+a^2-3a-5a+15)

We get rid of parentheses

a^2-3a-5a+15

We add all the numbers together, and all the variables

a^2-8a+15

Back to the equation:

-(a^2-8a+15)


We get rid of parentheses

a^2-a^2-5a-3a+8a+15-15=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0