(a-2)(a+4)+6=a

Solution for (a-2)(a+4)+6=a equation:

(a-2)(a+4)+6=a

We move all terms to the left:

(a-2)(a+4)+6-(a)=0

We add all the numbers together, and all the variables

-1a+(a-2)(a+4)+6=0

We multiply parentheses ..

(+a^2+4a-2a-8)-1a+6=0

We get rid of parentheses

a^2+4a-2a-1a-8+6=0

We add all the numbers together, and all the variables

a^2+a-2=0

a = 1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*1}=\frac{-4}{2}
=-2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*1}=\frac{2}{2}
=1
$