(a+ib)(a+ib)=2i

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Solution for (a+ib)(a+ib)=2i equation:


Simplifying
(a + ib)(a + ib) = 2i

Multiply (a + bi) * (a + bi)
(a(a + bi) + bi(a + bi)) = 2i
((a * a + bi * a) + bi(a + bi)) = 2i

Reorder the terms:
((abi + a2) + bi(a + bi)) = 2i
((abi + a2) + bi(a + bi)) = 2i
(abi + a2 + (a * bi + bi * bi)) = 2i
(abi + a2 + (abi + b2i2)) = 2i

Reorder the terms:
(abi + abi + a2 + b2i2) = 2i

Combine like terms: abi + abi = 2abi
(2abi + a2 + b2i2) = 2i

Solving
2abi + a2 + b2i2 = 2i

Solving for variable 'a'.

Combine like terms: 2i + -2i = 0
2abi + a2 + b2i2 + -2i = 0

The solution to this equation could not be determined.

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