(a+b)c=(b+a)c

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Solution for (a+b)c=(b+a)c equation:


Simplifying
(a + b) * c = (b + a) * c

Reorder the terms for easier multiplication:
c(a + b) = (b + a) * c
(a * c + b * c) = (b + a) * c
(ac + bc) = (b + a) * c

Reorder the terms:
ac + bc = (a + b) * c

Reorder the terms for easier multiplication:
ac + bc = c(a + b)
ac + bc = (a * c + b * c)
ac + bc = (ac + bc)

Add '-1ac' to each side of the equation.
ac + -1ac + bc = ac + -1ac + bc

Combine like terms: ac + -1ac = 0
0 + bc = ac + -1ac + bc
bc = ac + -1ac + bc

Combine like terms: ac + -1ac = 0
bc = 0 + bc
bc = bc

Add '-1bc' to each side of the equation.
bc + -1bc = bc + -1bc

Combine like terms: bc + -1bc = 0
0 = bc + -1bc

Combine like terms: bc + -1bc = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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