(a+b)(a+c)(b+c)=0

Solution for (a+b)(a+c)(b+c)=0 equation:

Simplifying
(a + b)(a + c)(b + c) = 0

Multiply (a + b) * (a + c)
(a(a + c) + b(a + c))(b + c) = 0
((a * a + c * a) + b(a + c))(b + c) = 0

Reorder the terms:
((ac + a2) + b(a + c))(b + c) = 0
((ac + a2) + b(a + c))(b + c) = 0
(ac + a2 + (a * b + c * b))(b + c) = 0
(ac + a2 + (ab + bc))(b + c) = 0

Reorder the terms:
(ab + ac + a2 + bc)(b + c) = 0
(ab + ac + a2 + bc)(b + c) = 0

Multiply (ab + ac + a2 + bc) * (b + c)
(ab(b + c) + ac(b + c) + a2(b + c) + bc(b + c)) = 0
((b * ab + c * ab) + ac(b + c) + a2(b + c) + bc(b + c)) = 0

Reorder the terms:
((abc + ab2) + ac(b + c) + a2(b + c) + bc(b + c)) = 0
((abc + ab2) + ac(b + c) + a2(b + c) + bc(b + c)) = 0
(abc + ab2 + (b * ac + c * ac) + a2(b + c) + bc(b + c)) = 0
(abc + ab2 + (abc + ac2) + a2(b + c) + bc(b + c)) = 0
(abc + ab2 + abc + ac2 + (b * a2 + c * a2) + bc(b + c)) = 0
(abc + ab2 + abc + ac2 + (a2b + a2c) + bc(b + c)) = 0
(abc + ab2 + abc + ac2 + a2b + a2c + (b * bc + c * bc)) = 0

Reorder the terms:
(abc + ab2 + abc + ac2 + a2b + a2c + (bc2 + b2c)) = 0
(abc + ab2 + abc + ac2 + a2b + a2c + (bc2 + b2c)) = 0

Reorder the terms:
(abc + abc + ab2 + ac2 + a2b + a2c + bc2 + b2c) = 0

Combine like terms: abc + abc = 2abc
(2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c) = 0

Solving
2abc + ab2 + ac2 + a2b + a2c + bc2 + b2c = 0

Solving for variable 'a'.

The solution to this equation could not be determined.