(a+5)(a-2)=(a+1)2

Solution for (a+5)(a-2)=(a+1)2 equation:

(a+5)(a-2)=(a+1)2

We move all terms to the left:

(a+5)(a-2)-((a+1)2)=0

We multiply parentheses ..

(+a^2-2a+5a-10)-((a+1)2)=0


We calculate terms in parentheses: -((a+1)2), so:

(a+1)2

We multiply parentheses

2a+2

Back to the equation:

-(2a+2)


We get rid of parentheses

a^2-2a+5a-2a-10-2=0

We add all the numbers together, and all the variables

a^2+a-12=0

a = 1; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·1·(-12)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*1}=\frac{-8}{2}
=-4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*1}=\frac{6}{2}
=3
$