(a+2a)=+(a+2a)=+(a+2a)

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Solution for (a+2a)=+(a+2a)=+(a+2a) equation: 



(a+2a)=+(a+2a)=+(a+2a)

We move all terms to the left:

(a+2a)-(+(a+2a))=0

We add all the numbers together, and all the variables

(+3a)-(+(+3a))=0

We get rid of parentheses

3a-(+(+3a))=0



We calculate terms in parentheses: -(+(+3a)), so:

+(+3a)

determiningTheFunctionDomain
(+3a)

We get rid of parentheses

3a

Back to the equation:

-(3a)



We add all the numbers together, and all the variables

=0

a=0/1

a=0

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