(a+10)/6=(a-4)/9

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Solution for (a+10)/6=(a-4)/9 equation: 



(a+10)/6=(a-4)/9

We move all terms to the left:

(a+10)/6-((a-4)/9)=0

We calculate fractions


a/()+(-((a-4)*6)/()=0



We calculate terms in parentheses: +(-((a-4)*6)/(), so:

-((a-4)*6)/(

We multiply all the terms by the denominator


-((a-4)*6)



We calculate terms in parentheses: -((a-4)*6), so:

(a-4)*6

We multiply parentheses

6a-24

Back to the equation:

-(6a-24)



We get rid of parentheses

-6a+24

Back to the equation:

+(-6a+24)



We get rid of parentheses

a/()-6a+24=0

We multiply all the terms by the denominator


a-6a*()+24*()=0

We add all the numbers together, and all the variables

a-6a*()=0

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