(a+1)/4+3a=4

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Solution for (a+1)/4+3a=4 equation:



(a+1)/4+3a=4
We move all terms to the left:
(a+1)/4+3a-(4)=0
We add all the numbers together, and all the variables
3a+(a+1)/4-4=0
We multiply all the terms by the denominator
3a*4+(a+1)-4*4=0
We add all the numbers together, and all the variables
3a*4+(a+1)-16=0
Wy multiply elements
12a+(a+1)-16=0
We get rid of parentheses
12a+a+1-16=0
We add all the numbers together, and all the variables
13a-15=0
We move all terms containing a to the left, all other terms to the right
13a=15
a=15/13
a=1+2/13

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