(a^2-b^2)(1-x^2)=4abx

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Solution for (a^2-b^2)(1-x^2)=4abx equation: 


Simplifying
(a2 + -1b2)(1 + -1x2) = 4abx

Multiply (a2 + -1b2) * (1 + -1x2)
(a2(1 + -1x2) + -1b2 * (1 + -1x2)) = 4abx
((1 * a2 + -1x2 * a2) + -1b2 * (1 + -1x2)) = 4abx
((1a2 + -1a2x2) + -1b2 * (1 + -1x2)) = 4abx
(1a2 + -1a2x2 + (1 * -1b2 + -1x2 * -1b2)) = 4abx
(1a2 + -1a2x2 + (-1b2 + 1b2x2)) = 4abx
(1a2 + -1a2x2 + -1b2 + 1b2x2) = 4abx

Solving
1a2 + -1a2x2 + -1b2 + 1b2x2 = 4abx

Solving for variable 'a'.

Reorder the terms:
-4abx + 1a2 + -1a2x2 + -1b2 + 1b2x2 = 4abx + -4abx

Combine like terms: 4abx + -4abx = 0
-4abx + 1a2 + -1a2x2 + -1b2 + 1b2x2 = 0

The solution to this equation could not be determined.

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