(Z+6)/3=2z/4

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Solution for (Z+6)/3=2z/4 equation: 


x in (-oo:+oo)

(Z+6)/3 = (2*z)/4 // - (2*z)/4

(Z+6)/3-((2*z)/4) = 0

(Z+6)/3+(-1/2)*z = 0

(Z+6)/3-z/2 = 0

(2*(Z+6))/(2*3)+(3*(-z))/(2*3) = 0

2*(Z+6)+3*(-z) = 0

2*Z-3*z+12 = 0

(2*Z-3*z+12)/(2*3) = 0

(2*Z-3*z+12)/(2*3) = 0 // * 2*3

2*Z-3*z+12 = 0

x belongs to the empty set

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