(Y-3)2+4(y-5)=-32

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Solution for (Y-3)2+4(y-5)=-32 equation: 



(-3)2+4(Y-5)=-32

We move all terms to the left:

(-3)2+4(Y-5)-(-32)=0

We add all the numbers together, and all the variables

4(Y-5)+26=0

We multiply parentheses

4Y-20+26=0

We add all the numbers together, and all the variables

4Y+6=0

We move all terms containing Y to the left, all other terms to the right

4Y=-6

Y=-6/4

Y=-1+1/2

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