(Xx5-4)=3(Xx3+8)

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Solution for (Xx5-4)=3(Xx3+8) equation: 



(XX5-4)=3(XX3+8)

We move all terms to the left:

(XX5-4)-(3(XX3+8))=0

We get rid of parentheses

XX5-(3(XX3+8))-4=0



We calculate terms in parentheses: -(3(XX3+8)), so:

3(XX3+8)

We multiply parentheses

3X+24

Back to the equation:

-(3X+24)



We get rid of parentheses

XX5-3X-24-4=0

We add all the numbers together, and all the variables

-3X+XX5-28=0

We move all terms containing X to the left, all other terms to the right

-3X+XX5=28

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