(X2+2x+1)2x-2=(5x+5)2x+2

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Solution for (X2+2x+1)2x-2=(5x+5)2x+2 equation: 



(X2+2X+1)2X-2=(5X+5)2X+2

We move all terms to the left:

(X2+2X+1)2X-2-((5X+5)2X+2)=0

We add all the numbers together, and all the variables

(+X^2+2X+1)2X-((5X+5)2X+2)-2=0

We multiply parentheses

2X^3+4X^2+2X-((5X+5)2X+2)-2=0



We calculate terms in parentheses: -((5X+5)2X+2), so:

(5X+5)2X+2

We multiply parentheses

10X^2+10X+2

Back to the equation:

-(10X^2+10X+2)



We do not support eXpression: X^3

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