(X/6)+(x/7)=(7/12)

Solution for (X/6)+(x/7)=(7/12) equation:

(X/6)+(X/7)=(7/12)

We move all terms to the left:

(X/6)+(X/7)-((7/12))=0

We add all the numbers together, and all the variables

(+X/6)+(+X/7)-((+7/12))=0

We get rid of parentheses

X/6+X/7-((+7/12))=0

We calculate fractions


84X^2/()+72X^2/()+()/()=0

We add all the numbers together, and all the variables

84X^2/()+72X^2/()+1=0

We multiply all the terms by the denominator


84X^2+72X^2+1*()=0

We add all the numbers together, and all the variables

156X^2=0

a = 156; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·156·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{312}=0$