(X-9)/2=(1+3x)/13

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Solution for (X-9)/2=(1+3x)/13 equation: 



(X-9)/2=(1+3X)/13

We move all terms to the left:

(X-9)/2-((1+3X)/13)=0

We add all the numbers together, and all the variables

(X-9)/2-((3X+1)/13)=0

We calculate fractions


X/()+(-((3X+1)*2)/()=0



We calculate terms in parentheses: +(-((3X+1)*2)/(), so:

-((3X+1)*2)/(

We multiply all the terms by the denominator


-((3X+1)*2)



We calculate terms in parentheses: -((3X+1)*2), so:

(3X+1)*2

We multiply parentheses

6X+2

Back to the equation:

-(6X+2)



We get rid of parentheses

-6X-2

Back to the equation:

+(-6X-2)



We get rid of parentheses

X/()-6X-2=0

We multiply all the terms by the denominator


X-6X*()-2*()=0

We add all the numbers together, and all the variables

X-6X*()=0

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