(X-8)(x-4)=x2-12x+

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Solution for (X-8)(x-4)=x2-12x+ equation:



(X-8)(X-4)=X2-12X+
We move all terms to the left:
(X-8)(X-4)-(X2-12X+)=0
We add all the numbers together, and all the variables
-(+X^2-12X+)+(X-8)(X-4)=0
We get rid of parentheses
-X^2+12X+(X-8)(X-4)-=0
We multiply parentheses ..
-X^2+(+X^2-4X-8X+32)+12X-=0
We add all the numbers together, and all the variables
-1X^2+(+X^2-4X-8X+32)+12X=0
We get rid of parentheses
-1X^2+X^2-4X-8X+12X+32=0
We add all the numbers together, and all the variables
32!=0
There is no solution for this equation

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