(X-7)(x-7)-4=(x+1)(x+1)

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Solution for (X-7)(x-7)-4=(x+1)(x+1) equation: 



(X-7)(X-7)-4=(X+1)(X+1)

We move all terms to the left:

(X-7)(X-7)-4-((X+1)(X+1))=0

We multiply parentheses ..

(+X^2-7X-7X+49)-((X+1)(X+1))-4=0



We calculate terms in parentheses: -((X+1)(X+1)), so:

(X+1)(X+1)

We multiply parentheses ..

(+X^2+X+X+1)

We get rid of parentheses

X^2+X+X+1

We add all the numbers together, and all the variables

X^2+2X+1

Back to the equation:

-(X^2+2X+1)



We get rid of parentheses

X^2-X^2-7X-7X-2X+49-1-4=0

We add all the numbers together, and all the variables

-16X+44=0

We move all terms containing X to the left, all other terms to the right

-16X=-44

X=-44/-16

X=2+3/4

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