(X-5)(x+8)=(x-2)(x+1+6)

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Solution for (X-5)(x+8)=(x-2)(x+1+6) equation: 



(X-5)(X+8)=(X-2)(X+1+6)

We move all terms to the left:

(X-5)(X+8)-((X-2)(X+1+6))=0

We add all the numbers together, and all the variables

(X-5)(X+8)-((X-2)(X+7))=0

We multiply parentheses ..

(+X^2+8X-5X-40)-((X-2)(X+7))=0



We calculate terms in parentheses: -((X-2)(X+7)), so:

(X-2)(X+7)

We multiply parentheses ..

(+X^2+7X-2X-14)

We get rid of parentheses

X^2+7X-2X-14

We add all the numbers together, and all the variables

X^2+5X-14

Back to the equation:

-(X^2+5X-14)



We get rid of parentheses

X^2-X^2+8X-5X-5X-40+14=0

We add all the numbers together, and all the variables

-2X-26=0

We move all terms containing X to the left, all other terms to the right

-2X=26

X=26/-2

X=-13

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