(X-5)(x+1)=(x+1)(x-4)

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Solution for (X-5)(x+1)=(x+1)(x-4) equation: 



(X-5)(X+1)=(X+1)(X-4)

We move all terms to the left:

(X-5)(X+1)-((X+1)(X-4))=0

We multiply parentheses ..

(+X^2+X-5X-5)-((X+1)(X-4))=0



We calculate terms in parentheses: -((X+1)(X-4)), so:

(X+1)(X-4)

We multiply parentheses ..

(+X^2-4X+X-4)

We get rid of parentheses

X^2-4X+X-4

We add all the numbers together, and all the variables

X^2-3X-4

Back to the equation:

-(X^2-3X-4)



We get rid of parentheses

X^2-X^2+X-5X+3X-5+4=0

We add all the numbers together, and all the variables

-1X-1=0

We move all terms containing X to the left, all other terms to the right

-X=1

X=1/-1

X=-1

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