(X-5)(3x-19)=0

Solution for (X-5)(3x-19)=0 equation:

(X-5)(3X-19)=0

We multiply parentheses ..

(+3X^2-19X-15X+95)=0

We get rid of parentheses

3X^2-19X-15X+95=0

We add all the numbers together, and all the variables

3X^2-34X+95=0

a = 3; b = -34; c = +95;
Δ = b2-4ac
Δ = -342-4·3·95
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-4}{2*3}=\frac{30}{6}
=5
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+4}{2*3}=\frac{38}{6}
=6+1/3
$