(X-4)/(2x+3)=11x+7

Solution for (X-4)/(2x+3)=11x+7 equation:

(X-4)/(2X+3)=11X+7

We move all terms to the left:

(X-4)/(2X+3)-(11X+7)=0


Domain of the equation: (2X+3)!=0

We move all terms containing X to the left, all other terms to the right

2X!=-3

X!=-3/2

X!=-1+1/2

X∈R


We get rid of parentheses

(X-4)/(2X+3)-11X-7=0

We multiply all the terms by the denominator


(X-4)-11X*(2X+3)-7*(2X+3)=0

We multiply parentheses

-22X^2+(X-4)-33X-14X-21=0

We get rid of parentheses

-22X^2+X-33X-14X-4-21=0

We add all the numbers together, and all the variables

-22X^2-46X-25=0

a = -22; b = -46; c = -25;
Δ = b2-4ac
Δ = -462-4·(-22)·(-25)
Δ = -84
Delta is less than zero, so there is no solution for the equation