(X-4)(x+2)=x(x-3)+5

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Solution for (X-4)(x+2)=x(x-3)+5 equation: 



(X-4)(X+2)=X(X-3)+5

We move all terms to the left:

(X-4)(X+2)-(X(X-3)+5)=0

We multiply parentheses ..

(+X^2+2X-4X-8)-(X(X-3)+5)=0



We calculate terms in parentheses: -(X(X-3)+5), so:

X(X-3)+5

We multiply parentheses

X^2-3X+5

Back to the equation:

-(X^2-3X+5)



We get rid of parentheses

X^2-X^2+2X-4X+3X-8-5=0

We add all the numbers together, and all the variables

X-13=0

We move all terms containing X to the left, all other terms to the right

X=13

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