(X-3)/2=(x+1)/5

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Solution for (X-3)/2=(x+1)/5 equation: 



(X-3)/2=(X+1)/5

We move all terms to the left:

(X-3)/2-((X+1)/5)=0

We calculate fractions


X/()+(-((X+1)*2)/()=0



We calculate terms in parentheses: +(-((X+1)*2)/(), so:

-((X+1)*2)/(

We multiply all the terms by the denominator


-((X+1)*2)



We calculate terms in parentheses: -((X+1)*2), so:

(X+1)*2

We multiply parentheses

2X+2

Back to the equation:

-(2X+2)



We get rid of parentheses

-2X-2

Back to the equation:

+(-2X-2)



We get rid of parentheses

X/()-2X-2=0

We multiply all the terms by the denominator


X-2X*()-2*()=0

We add all the numbers together, and all the variables

X-2X*()=0

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