(X-3)(x-4)=x2+4

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Solution for (X-3)(x-4)=x2+4 equation: 



(X-3)(X-4)=X2+4

We move all terms to the left:

(X-3)(X-4)-(X2+4)=0

We add all the numbers together, and all the variables

-(+X^2+4)+(X-3)(X-4)=0

We get rid of parentheses

-X^2+(X-3)(X-4)-4=0

We multiply parentheses ..

-X^2+(+X^2-4X-3X+12)-4=0

We add all the numbers together, and all the variables

-1X^2+(+X^2-4X-3X+12)-4=0

We get rid of parentheses

-1X^2+X^2-4X-3X+12-4=0

We add all the numbers together, and all the variables

-7X+8=0

We move all terms containing X to the left, all other terms to the right

-7X=-8

X=-8/-7

X=1+1/7

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