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(X-3)(X-3)=55
We move all terms to the left:
(X-3)(X-3)-(55)=0
We multiply parentheses ..
(+X^2-3X-3X+9)-55=0
We get rid of parentheses
X^2-3X-3X+9-55=0
We add all the numbers together, and all the variables
X^2-6X-46=0
a = 1; b = -6; c = -46;
Δ = b2-4ac
Δ = -62-4·1·(-46)
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{55}}{2*1}=\frac{6-2\sqrt{55}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{55}}{2*1}=\frac{6+2\sqrt{55}}{2} $
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