(X-3)(x-3)-6(x-3)+9=0

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Solution for (X-3)(x-3)-6(x-3)+9=0 equation: 



(X-3)(X-3)-6(X-3)+9=0

We multiply parentheses

(X-3)(X-3)-6X+18+9=0

We multiply parentheses ..

(+X^2-3X-3X+9)-6X+18+9=0

We add all the numbers together, and all the variables

(+X^2-3X-3X+9)-6X+27=0

We get rid of parentheses

X^2-3X-3X-6X+9+27=0

We add all the numbers together, and all the variables

X^2-12X+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{12}{2}=6$

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