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(X-2)(X-3)=5-2X
We move all terms to the left:
(X-2)(X-3)-(5-2X)=0
We add all the numbers together, and all the variables
(X-2)(X-3)-(-2X+5)=0
We get rid of parentheses
(X-2)(X-3)+2X-5=0
We multiply parentheses ..
(+X^2-3X-2X+6)+2X-5=0
We get rid of parentheses
X^2-3X-2X+2X+6-5=0
We add all the numbers together, and all the variables
X^2-3X+1=0
a = 1; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·1·1
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{5}}{2*1}=\frac{3-\sqrt{5}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{5}}{2*1}=\frac{3+\sqrt{5}}{2} $
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